{"id":479,"date":"2021-09-04T16:51:54","date_gmt":"2021-09-04T16:51:54","guid":{"rendered":"https:\/\/blog.metu.edu.tr\/eresmech\/?page_id=479"},"modified":"2023-06-14T09:27:11","modified_gmt":"2023-06-14T09:27:11","slug":"8-5","status":"publish","type":"page","link":"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-5\/","title":{"rendered":"8-5"},"content":{"rendered":"<div id=\"pl-gb479-69d7c015048ed\"  class=\"panel-layout\" ><div id=\"pg-gb479-69d7c015048ed-0\"  class=\"panel-grid panel-no-style\" ><div id=\"pgc-gb479-69d7c015048ed-0-0\"  class=\"panel-grid-cell\" ><div id=\"panel-gb479-69d7c015048ed-0-0-0\" class=\"so-panel widget widget_sow-editor panel-first-child panel-last-child widgetopts-SO\" data-index=\"0\" ><div\n\t\t\t\n\t\t\tclass=\"so-widget-sow-editor so-widget-sow-editor-base\"\n\t\t\t\n\t\t>\n<div class=\"siteorigin-widget-tinymce textwidget\">\n\t<h1><strong data-rich-text-format-boundary=\"true\">8.5 Kam Profilinin Elde Edilmesi<\/strong><\/h1>\n<p>Temel dairesi yar\u0131\u00e7ap\u0131 ve hareket diyagram\u0131 belirlendikten sonra kam profilinin elde edilmesi i\u00e7in \u00f6nceden toparlakl\u0131 santrik izleyicili radyal kamda a\u00e7\u0131kland\u0131\u011f\u0131 gibi, kinematik yer de\u011fi\u015fim yap\u0131larak, kam sabit tutulur. Sabit uzuv kama g\u00f6re d\u00f6necek (kam\u0131n sabit uzva g\u00f6re d\u00f6nme y\u00f6n\u00fcn\u00fcn ters y\u00f6n\u00fcnde) ve bu arada izleyici ba\u011f\u0131l konumu hareket e\u011frisine g\u00f6re belirlenecektir. \u0130zleyicinin her kam a\u00e7\u0131s\u0131na g\u00f6re ald\u0131\u011f\u0131 konum bir e\u011fri demetini olu\u015fturacakt\u0131r. Bu e\u011fri demetinin her bir e\u011frisine te\u011fet olarak \u00e7izilen e\u011fri kam profilidir. A\u015fa\u011f\u0131daki \u015fekilde ise d\u00fcz y\u00fczeyli \u00f6teleme yapan izleyicili radyal kam profilinin belirli bir hareket e\u011frisi i\u00e7in elde edilmesi g\u00f6sterilmektedir.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-481\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img5-3.gif\" alt=\"\" width=\"757\" height=\"592\" \/><\/p>\n<p style=\"text-align: left\" align=\"center\"><div class=\"su-image-carousel  su-image-carousel-has-spacing su-image-carousel-has-lightbox su-image-carousel-has-outline su-image-carousel-adaptive su-image-carousel-slides-style-default su-image-carousel-controls-style-dark su-image-carousel-align-center\" style=\"max-width:700px\" data-flickity-options='{\"groupCells\":true,\"cellSelector\":\".su-image-carousel-item\",\"adaptiveHeight\":true,\"cellAlign\":\"left\",\"prevNextButtons\":true,\"pageDots\":false,\"autoPlay\":false,\"imagesLoaded\":true,\"contain\":false,\"selectedAttraction\":1,\"friction\":1}' id=\"su_image_carousel_69d7c01506ac8\"><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_1.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_1.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_2.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_2.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_3.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_3.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_4.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_4.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_5.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_5.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_6.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/kammotion2_6.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/09\/kammotion2e_7.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/09\/kammotion2e_7.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><\/div><script id=\"su_image_carousel_69d7c01506ac8_script\">if(window.SUImageCarousel){setTimeout(function() {window.SUImageCarousel.initGallery(document.getElementById(\"su_image_carousel_69d7c01506ac8\"))}, 0);}var su_image_carousel_69d7c01506ac8_script=document.getElementById(\"su_image_carousel_69d7c01506ac8_script\");if(su_image_carousel_69d7c01506ac8_script){su_image_carousel_69d7c01506ac8_script.parentNode.removeChild(su_image_carousel_69d7c01506ac8_script);}<\/script><\/p>\n<p>Kam profilini geometrik olarak belirli bir hassasiyette elde edilebilmesi \u00e7ok s\u0131k aral\u0131klarda izleyicinin kama g\u00f6re ba\u011f\u0131l konumunun bulunmas\u0131n\u0131 gerektirir. Bilgisayarda bu geometrik y\u00f6ntem bir \u00e7izim program\u0131 kullan\u0131larak uygulansa bile i\u015flem uzun ve yorucudur. Ayr\u0131ca g\u00fcn\u00fcm\u00fczde kam imalat\u0131 i\u00e7in numerik kontrollu tak\u0131m tezgahlar\u0131 kullan\u0131ld\u0131\u011f\u0131ndan bu tezgahlar i\u00e7in kam profili noktalar\u0131n\u0131 numerik olarak hassas bir \u015fekilde bulmam\u0131z laz\u0131md\u0131r. Bu nedenlerden dolay\u0131 analitik olarak kam profilinin belirlenmesi a\u00e7\u0131klanacakt\u0131r.<\/p>\n<p>Kam profilinin analitik olarak belirlenmesi matematik\u00e7iler taraf\u0131ndan geli\u015ftirilmi\u015f olan zarf teorisi ile m\u00fcmk\u00fcnd\u00fcr. Matematiksel olarak zarf:<\/p>\n<p style=\"padding-left: 40px\"><i>Bir e\u011fri demeti i\u00e7inde bulunan her bir e\u011fri bir ba\u015fka e\u011friye te\u011fet ve bu e\u011frinin her bir noktas\u0131nda, demeti olu\u015fturan e\u011frilerden birisi bu e\u011friye te\u011fet ise, bu e\u011fri bir zarf\u0131n t\u00fcm\u00fc veya bir par\u00e7as\u0131d\u0131r.<\/i><\/p>\n<p>Bir parametreli e\u011fri demeti f(x, y, c) = 0 gibi bir denklemle belirlidir. Bu denklemde c de\u011fi\u015fken parametre olup her c de\u011ferinde e\u011fri demetinin bir e\u011frisi elde edilir. f(x, y, c) fonksiyonunun s\u00fcrekli oldu\u011funu (istenilen t\u00fcrevlerinin x, y, c parametrelerine g\u00f6re al\u0131nabilece\u011fini ve bu t\u00fcrevlerin sonlu de\u011ferler oldu\u011fu) varsay\u0131lacakt\u0131r.<\/p>\n<p>Bu e\u011fri demetinde bulunan bir e\u011frinin her hangi bir noktas\u0131nda e\u011fimi:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{\\text{dy}}}{{\\text{dx}}}=-\\frac{{\\partial \\text{f\/}\\partial \\text{x}}}{{\\partial \\text{f\/}\\partial \\text{y}}} <\/span><\/p>\n<p>d\u0131. Bu denklemden:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{\\partial \\text{f}}}{{\\partial \\text{x}}}\\text{dx}+\\frac{{\\partial \\text{f}}}{{\\partial \\text{y}}}\\text{dy}=0 <\/span><\/p>\n<p>ba\u011f\u0131nt\u0131s\u0131 elde edilir. Bu ba\u011f\u0131nt\u0131 ayn\u0131 zamanda:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{\\partial \\text{f}}}{{\\partial \\text{x}}}\\frac{\\text{dx}}{{\\text{dc}}}+\\frac{{\\partial \\text{f}}}{{\\partial \\text{y}}}\\frac{\\text{dy}}{{\\text{dc}}}=0 <\/span><\/p>\n<p>olarak yaz\u0131labilir. E\u011fim denkleminden elde edilen bu ili\u015fki demetin i\u00e7inde bulunan her e\u011fri i\u00e7in ge\u00e7erli olacakt\u0131r. E\u011fer bir ba\u015fka e\u011fri (zarf) bu e\u011fri demetini olu\u015fturan e\u011frilere te\u011fet ise, o e\u011frininde ayn\u0131 ili\u015fkiyi sa\u011flamas\u0131 gerekir.<\/p>\n<p>f(x, y, c) = 0 fonksiyonunun toplam t\u00fcrevi:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{\\partial \\text{f}}}{{\\partial \\text{x}}}\\text{dx}+\\frac{{\\partial \\text{f}}}{{\\partial \\text{y}}}\\text{dy}+\\frac{{\\partial \\text{f}}}{{\\partial \\text{c}}}\\text{dc}=0 <\/span><\/p>\n<p>d\u0131r, veya:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{\\partial \\text{f}}}{{\\partial \\text{x}}}\\frac{\\text{dx}}{{\\text{dc}}}+\\frac{{\\partial \\text{f}}}{{\\partial \\text{y}}}\\frac{\\text{dy}}{{\\text{dc}}}+\\frac{{\\partial \\text{f}}}{{\\partial \\text{c}}}=0 <\/span><\/p>\n<p>olacakt\u0131r. E\u011fim denkleminden elde edilmi\u015f olan ili\u015fki bu denklemde kullan\u0131ld\u0131\u011f\u0131nda:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{\\partial \\text{f}}}{{\\partial \\text{c}}}={{\\text{f}}_{\\text{c}}}=0 <\/span><\/p>\n<p>olacakt\u0131r. \u00d6\u011fle ise bu e\u011fri demetinin zarf\u0131 f(x, y, c) = 0 denklemini sa\u011flamas\u0131 gerekti\u011fi gibi f<sub>c<\/sub> = 0 k\u0131smi t\u00fcrevini de sa\u011flamal\u0131d\u0131r. Bu iki denklemden c parametresinin yok edilmesi ile elde edilen g(x, y) = 0 e\u011frisi e\u011fri demetinin zarf\u0131d\u0131r.<\/p>\n<p>Bazi durumlarda bir e\u011fri demeti parametrik denklem \u015feklinde g\u00f6sterilebilir. Yani, e\u011fri demeti:<\/p>\n<p style=\"padding-left: 40px\">x = \u03d5(s, c)<\/p>\n<p style=\"padding-left: 40px\">y = \u03c8(s, c)<\/p>\n<p>\u015feklinde verilebilir. Burada s e\u011fri parametresi, c ise demet parametresidir. Zarf bu denklemlerden ve:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{\\partial \\text{\u03d5}}}{{\\partial \\text{s}}}\\frac{{\\partial \\text{\u03c8}}}{{\\partial \\text{c}}}-\\frac{{\\partial \\text{\u03d5}}}{{\\partial \\text{c}}}\\frac{{\\partial \\text{\u03c8}}}{{\\partial \\text{s}}}=0 <\/span><\/p>\n<p>denkleminden c parametresinin yok edilmesi ile elde edilir.<\/p>\n<p><strong>\u00d6rnek 4:<\/strong><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-500\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img6-3.gif\" alt=\"\" width=\"517\" height=\"213\" \/><\/p>\n<p style=\"text-align: center\">f(x, y, c) = (x \u2212 c)<sup>2<\/sup> + y<sup>2<\/sup> \u2212 1 = 0<\/p>\n<p>denklemi ile verilen e\u011fri demetinin zarf\u0131n\u0131 bulal\u0131m. \u015eekilde g\u00f6sterildi\u011fi gibi, e\u011fri demeti merkezi x = c ve y = 0 ve yar\u0131\u00e7ap\u0131 bir birim olan dairelerdir. Her c de\u011feri i\u00e7in demetin bir e\u011frisi elde edilir. Denklemin c parametresine g\u00f6re t\u00fcrevi:<\/p>\n<p style=\"text-align: center\">f<sub>c<\/sub> = \u22122(x \u2212 c) = 0<\/p>\n<p>f ve f<sub>c<\/sub>\u00a0denklemlerinden c parametresi yok edildi\u011finde:<\/p>\n<p style=\"text-align: center\">y = \u00b11<\/p>\n<p>elde edilir. Bu zarf e\u011frisi, \u015fekilde g\u00f6r\u00fcld\u00fc\u011f\u00fc gibi daire demetine te\u011fet, yatay do\u011frulard\u0131r.<\/p>\n<p><strong>\u00d6rnek 5:<\/strong><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-501 aligncenter\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img7-2.gif\" alt=\"\" width=\"405\" height=\"433\" \/><div class=\"su-image-carousel  su-image-carousel-has-spacing su-image-carousel-has-lightbox su-image-carousel-has-outline su-image-carousel-adaptive su-image-carousel-slides-style-default su-image-carousel-controls-style-dark su-image-carousel-align-center\" style=\"max-width:700px\" data-flickity-options='{\"groupCells\":true,\"cellSelector\":\".su-image-carousel-item\",\"adaptiveHeight\":true,\"cellAlign\":\"left\",\"prevNextButtons\":true,\"pageDots\":false,\"autoPlay\":false,\"imagesLoaded\":true,\"contain\":false,\"selectedAttraction\":1,\"friction\":1}' id=\"su_image_carousel_69d7c01507374\"><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/fallingladder.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"488\" height=\"389\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/fallingladder.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/fallingladder1.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"444\" height=\"381\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/fallingladder1.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><\/div><script id=\"su_image_carousel_69d7c01507374_script\">if(window.SUImageCarousel){setTimeout(function() {window.SUImageCarousel.initGallery(document.getElementById(\"su_image_carousel_69d7c01507374\"))}, 0);}var su_image_carousel_69d7c01507374_script=document.getElementById(\"su_image_carousel_69d7c01507374_script\");if(su_image_carousel_69d7c01507374_script){su_image_carousel_69d7c01507374_script.parentNode.removeChild(su_image_carousel_69d7c01507374_script);}<\/script><\/p>\n<p>Bir ucu duvara dayal\u0131, bir ucu yerde duran bir merdivenin s\u00fcrt\u00fcnmenin az olmas\u0131ndan dolay\u0131 d\u00fc\u015ferken yapt\u0131\u011f\u0131 hareketi ele alal\u0131m. Merdivenin farkl\u0131 konumlar\u0131 bir e\u011fri demetini olu\u015fturacakt\u0131r. Bu s\u0131rada olu\u015fturulan zarf\u0131 bulal\u0131m:<\/p>\n<p>Parametrik olarak merdivenin denklemi:<\/p>\n<p style=\"padding-left: 40px\">y = \u2212x tan\u03b3 + <em>l<\/em> sin\u03b3<\/p>\n<p>dir. \u03b3 merdiven ile yatay arasinda kalan a\u00e7i,\u00a0<i>l<\/i>\u00a0ise merdiven uzunlu\u011fudur. Bu denklemi:<\/p>\n<p style=\"padding-left: 40px\">f(x, y, \u03b3) = y + x tan\u03b3 \u2212 <em>l<\/em> sin\u03b3 = 0<\/p>\n<p>\u015feklinde yazabiliriz. Denklemin \u03b3\u00a0ya g\u00f6re k\u0131smi t\u00fcrevi ise:<\/p>\n<p style=\"padding-left: 40px\">f<sub>\u03b3<\/sub>(x, y, \u03b3) = x\/cos<sup>2<\/sup>\u03b3 \u2212 <em>l<\/em> cos\u03b3 = 0<\/p>\n<p>olacakt\u0131r. Bu iki denklemden x ve y i\u00e7in \u00e7\u00f6z\u00fcm yap\u0131ld\u0131\u011f\u0131nda:<\/p>\n<p style=\"padding-left: 40px\">x =\u00a0<em>l<\/em> cos<sup>3<\/sup>\u03b3<\/p>\n<p style=\"padding-left: 40px\">y = <em>l<\/em> sin<sup>3<\/sup>\u03b3<\/p>\n<p>dir. Bu iki denklem zarf e\u011frisini parametrik olarak tanimlamaktadir ve zarf bu denklemlerle \u00e7izilebilir. E\u011fer \u03b3 parametresini bu iki denklemden yok edersek:<\/p>\n<p style=\"padding-left: 40px\">x<sup>2\/3<\/sup> + y<sup>2\/3<\/sup> = <em>l<\/em><sup>2\/3<\/sup><\/p>\n<p>denklemi elde edilir (bu astroid e\u011frisidir).<\/p>\n<p><strong>\u00d6rnek 6:<\/strong><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-502\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img8-1.gif\" alt=\"\" width=\"520\" height=\"186\" \/><\/p>\n<p>Bir top kullan\u0131larak ilk h\u0131z\u0131 v olan mermiyi yatay ile \u03b1 a\u00e7\u0131s\u0131 yapacak \u015fekilde at\u0131yoruz. Bu merminin etkisi alt\u0131nda olabilecek alan (vurabilece\u011fimiz hedefler) neresidir.<\/p>\n<p>Problem klasik e\u011fik at\u0131\u015f problemidir. Mermi x y\u00f6n\u00fcnde sabit h\u0131z, y y\u00f6n\u00fcnde ise sabit yer \u00e7ekimi ivmesi ile hareket edece\u011finden e\u011fri demeti parametrik olarak:<\/p>\n<p style=\"padding-left: 40px\">x = v cos(\u03b1t)<\/p>\n<p style=\"padding-left: 40px\">y = v sin(\u03b1t) \u2212 \u00bdgt<sup>2<\/sup><\/p>\n<p>dir. Denklemlerden t parametresi yok edildi\u011finde:<\/p>\n<p style=\"padding-left: 40px\">f(x, y, \u03b1) = \u00bdx<sup>2<\/sup> \u2212 [(v<sup>2<\/sup>\/g)sin\u03b1cos\u03b1]x + [(v<sup>2<\/sup>\/g)cos<sup>2<\/sup>\u03b1]y = 0<\/p>\n<p>parabol e\u011frisi elde edilir. Denklemin \u03b1 parametresine g\u00f6re t\u00fcrevi:<\/p>\n<p style=\"padding-left: 40px\">f<sub>\u03b1<\/sub>(x, y, \u03b1) = \u2212(v<sup>2<\/sup>\/g)[x(cos<sup>2<\/sup>\u03b1 \u2212 sin<sup>2<\/sup>\u03b1) + 2ysin\u03b1cos\u03b1] = 0<\/p>\n<p>d\u0131r. Bu denklem basitle\u015ftirildi\u011finde:<\/p>\n<p style=\"padding-left: 40px\">cos(2\u03b1) x + sin(2\u03b1) y = 0<\/p>\n<p>\u015feklinde yaz\u0131labilir. f(x, y, \u03b1) ve f<sub>\u03b1<\/sub>(x, y, \u03b1) denklemlerinden \u03b1 yok edildi\u011finde zarf e\u011frisi:<\/p>\n<p style=\"padding-left: 40px\">y = \u00bd[v<sup>2<\/sup>\/g \u2212 gx<sup>2<\/sup>\/v<sup>2<\/sup>]\n<p>\u015feklinde bulunur. Bu denklem bir parabold\u00fcr. Sonu\u00e7 asa\u011f\u0131da g\u00f6sterilmektedir. Bu zarf e\u011frisinin (parabol\u00fcn) alt\u0131nda kalan noktalara at\u0131\u015f yap\u0131labilir.<\/p>\n<div class=\"su-image-carousel  su-image-carousel-has-spacing su-image-carousel-has-lightbox su-image-carousel-has-outline su-image-carousel-adaptive su-image-carousel-slides-style-default su-image-carousel-controls-style-dark su-image-carousel-align-center\" style=\"max-width:700px\" data-flickity-options='{\"groupCells\":true,\"cellSelector\":\".su-image-carousel-item\",\"adaptiveHeight\":true,\"cellAlign\":\"left\",\"prevNextButtons\":true,\"pageDots\":false,\"autoPlay\":false,\"imagesLoaded\":true,\"contain\":false,\"selectedAttraction\":1,\"friction\":1}' id=\"su_image_carousel_69d7c01507be7\"><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/egikatis1-1.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/egikatis1-1.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/egikatis2-1.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"400\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/egikatis2-1.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><\/div><script id=\"su_image_carousel_69d7c01507be7_script\">if(window.SUImageCarousel){setTimeout(function() {window.SUImageCarousel.initGallery(document.getElementById(\"su_image_carousel_69d7c01507be7\"))}, 0);}var su_image_carousel_69d7c01507be7_script=document.getElementById(\"su_image_carousel_69d7c01507be7_script\");if(su_image_carousel_69d7c01507be7_script){su_image_carousel_69d7c01507be7_script.parentNode.removeChild(su_image_carousel_69d7c01507be7_script);}<\/script>\n<p>Yukar\u0131da anlat\u0131lm\u0131\u015f olan zarf teorisinin kam mekanizmalar\u0131na uygulamalar\u0131 olarak:<\/p>\n<p><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/top\/\" target=\"_blank\" rel=\"noopener\"><span style=\"text-decoration: underline\">A-) Toparlakl\u0131, \u00f6teleme yapan izleyicili radyal kam profili i\u00e7in buray\u0131 t\u0131klay\u0131n.<\/span><\/a><br \/>\n<a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/duz\/\" target=\"_blank\" rel=\"noopener\"><span style=\"text-decoration: underline\">B-) D\u00fcz y\u00fczeyli \u00f6teleme yapan izleyicili radyal kam profili i\u00e7in buray\u0131 t\u0131klay\u0131n.<\/span><\/a><br \/>\n<a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/topsal\/\" target=\"_blank\" rel=\"noopener\"><span style=\"text-decoration: underline\">C-) Toparlakl\u0131 sal\u0131n\u0131m yapan izleyicili kam profili i\u00e7in buray\u0131 t\u0131klay\u0131n.<\/span><\/a><br \/>\n<a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/topsalkap\/\" target=\"_blank\" rel=\"noopener\"><span style=\"text-decoration: underline\">D-) \u015eekil kapal\u0131 kam profili i\u00e7in buray\u0131 t\u0131klay\u0131n.<\/span><\/a><\/p>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div>\n\n\n<p><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-4\/\" data-type=\"page\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-16\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/back_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/\" data-type=\"page\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-17\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/contents_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/\" data-type=\"page\" data-id=\"47\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-18\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/home_button.gif\" alt=\"\" \/><\/a><img loading=\"lazy\" decoding=\"async\" width=\"119\" height=\"40\" class=\"wp-image-15\" style=\"width: 119px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/ceres.gif\" alt=\"\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>8.5 Kam Profilinin Elde Edilmesi Temel dairesi yar\u0131\u00e7ap\u0131 ve hareket diyagram\u0131 belirlendikten sonra kam profilinin elde edilmesi i\u00e7in \u00f6nceden toparlakl\u0131 santrik izleyicili radyal kamda a\u00e7\u0131kland\u0131\u011f\u0131 gibi, kinematik yer de\u011fi\u015fim yap\u0131larak, kam sabit tutulur. Sabit uzuv kama g\u00f6re d\u00f6necek (kam\u0131n sabit &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-5\/\"> <span class=\"screen-reader-text\">8-5<\/span> Devam\u0131n\u0131 Oku &raquo;<\/a><\/p>\n","protected":false},"author":7747,"featured_media":0,"parent":371,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":"","_links_to":"","_links_to_target":""},"class_list":["post-479","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/479","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/users\/7747"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/comments?post=479"}],"version-history":[{"count":0,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/479\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/371"}],"wp:attachment":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/media?parent=479"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}