{"id":465,"date":"2021-09-04T16:12:38","date_gmt":"2021-09-04T16:12:38","guid":{"rendered":"https:\/\/blog.metu.edu.tr\/eresmech\/?page_id=465"},"modified":"2021-10-05T20:48:41","modified_gmt":"2021-10-05T20:48:41","slug":"8-4","status":"publish","type":"page","link":"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-4\/","title":{"rendered":"8-4"},"content":{"rendered":"<div id=\"pl-gb465-69d7dade24755\"  class=\"panel-layout\" ><div id=\"pg-gb465-69d7dade24755-0\"  class=\"panel-grid panel-no-style\" ><div id=\"pgc-gb465-69d7dade24755-0-0\"  class=\"panel-grid-cell\" ><div id=\"panel-gb465-69d7dade24755-0-0-0\" class=\"so-panel widget widget_sow-editor panel-first-child panel-last-child widgetopts-SO\" data-index=\"0\" ><div\n\t\t\t\n\t\t\tclass=\"so-widget-sow-editor so-widget-sow-editor-base\"\n\t\t\t\n\t\t>\n<div class=\"siteorigin-widget-tinymce textwidget\">\n\t<h1><strong data-rich-text-format-boundary=\"true\">8.4 Kam Boyutu Belirleme<\/strong><\/h1>\n<p>Amac\u0131m\u0131z elde etti\u011fimiz hareket e\u011frisini verecek bir kam profilini elde etmektir. Ayn\u0131 hareket e\u011frisini verecek farkl\u0131 boyutlarda kam imal edilebilir. Kam boyutlar\u0131n\u0131 kar\u015f\u0131la\u015ft\u0131rmak i\u00e7in temel daire \u00e7ap\u0131 esas al\u0131nacakt\u0131r. Uygulamalarda kam boyutunu m\u00fcmk\u00fcn oldu\u011funca k\u00fc\u00e7\u00fck almak istenir. Bunun nedeni kam boyutu b\u00fcy\u00fcd\u00fck\u00e7e:<\/p>\n<ol>\n<li>\u00a0 \u00a0 \u00a0Daha fazla alan kapsayacakt\u0131r.<\/li>\n<li>\u00a0 \u00a0 \u00a0Dengesiz k\u00fctle artacakt\u0131r.<\/li>\n<li>\u00a0 \u00a0 \u00a0\u0130zleyici toparla\u011f\u0131 bir devirde daha uzun bir y\u00f6r\u00fcnge izleyecek, y\u00fczey h\u0131z\u0131 artacakt\u0131r.<\/li>\n<\/ol>\n<p>Ancak Kam boyutu k\u00fc\u00e7\u00fcld\u00fck\u00e7e mekanizmada baz\u0131 sak\u0131ncalar olu\u015facakt\u0131r. Bunlar:<\/p>\n<ol>\n<li>\u00a0 \u00a0 \u00a0Kam profili daha dik e\u011fimli olacak ve ba\u011flama a\u00e7\u0131s\u0131 daha k\u00f6t\u00fc de\u011ferlerde olacakt\u0131r.<\/li>\n<li>\u00a0 \u00a0 \u00a0Kam profilinde e\u011frilik yar\u0131\u00e7ap\u0131 \u00e7ok d\u00fc\u015f\u00fck veya e\u011fri oldu\u011fu k\u0131s\u0131mlar olacakt\u0131r (ki bu durumda kam \u00e7al\u0131\u015famaz).<\/li>\n<li>\u00a0 \u00a0 \u00a0Belirli bir y\u00fck alt\u0131nda \u00e7al\u0131\u015fan kam\u0131n kam milinin etki eden momente g\u00f6re hesaplanan bir \u00e7ap\u0131 vard\u0131r. Kam\u0131n temel daire \u00e7ap\u0131 mil \u00e7ap\u0131ndan k\u00fc\u00e7\u00fck olamaz (bu husus bilhassa motor kamlar\u0131nda \u00f6nemlidir).<\/li>\n<\/ol>\n<p>Uygulamada ba\u011flama a\u00e7\u0131s\u0131 kam\u0131n minimum gerekli boyutunu belirlemekte kullan\u0131l\u0131r. Di\u011fer hususlar (\u00f6rne\u011fin minimum e\u011frilik yar\u0131\u00e7ap\u0131, vb), kullan\u0131larak gerekti\u011finde bulunan bu minimum boyut art\u0131r\u0131l\u0131r.<\/p>\n<h1><strong data-rich-text-format-boundary=\"true\">Ba\u011flama A\u00e7\u0131s\u0131<\/strong><\/h1>\n<p>D\u00f6rd\u00fcnc\u00fc b\u00f6l\u00fcmde belirtildi\u011fi gibi, ba\u011flama a\u00e7\u0131s\u0131 bir mekanizmada kuvvet iletimi \u00f6zelliklerini belirleyen en basit ve kolay kinematik parametredir. D\u00f6rd\u00fcnc\u00fc b\u00f6l\u00fcmde verilmi\u015f olan tan\u0131ma g\u00f6re:<\/p>\n<p style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {\\tan \\text{\u03bc}=\\frac{\\text{\u0130zleyici uzvunu hareket ettirmeye \u00e7al\u0131\u015fan kuvvet bile\u015fkesi}}{\\text{\u0130zleyici uzvu yataklar\u0131nda yatak kuvveti olu\u015fturan kuvvet bile\u015fkesi}}}<\/span><\/p>\n<p>dir. Bu tan\u0131ma g\u00f6re \u015fekilde toparlakl\u0131 \u00f6teleyen ve sal\u0131nan kam mekanizmalar\u0131 i\u00e7in ba\u011flama a\u00e7\u0131s\u0131 g\u00f6sterilmi\u015ftir. D\u00fcz y\u00fczeyli izleyiciler i\u00e7in ba\u011flama a\u00e7\u0131s\u0131 tan\u0131m\u0131 kullan\u0131lamaz. Ayr\u0131ca kuvvet kapal\u0131 kamlarda y\u00fckselme s\u0131ras\u0131nda izleyici kam taraf\u0131ndan itilecektir, geri d\u00f6n\u00fc\u015f s\u0131ras\u0131nda ise genellikle yay ile olu\u015fturulan d\u0131\u015f kuvvet izleyici ile kam aras\u0131nda temes\u0131 sa\u011flayacak, kam taraf\u0131ndan izleyiciye bir kuvvet iletilmeyecektir. Bu nedenle kuvvet kapal\u0131 kamlarda y\u00fckselme s\u0131ras\u0131nda ba\u011flama a\u00e7\u0131s\u0131 \u00f6nemlidir.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-471 aligncenter\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img1-4.gif\" alt=\"\" width=\"479\" height=\"244\" \/><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-472\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img2-4.gif\" alt=\"\" width=\"313\" height=\"604\" \/><div class=\"su-image-carousel  su-image-carousel-has-spacing su-image-carousel-has-lightbox su-image-carousel-has-outline su-image-carousel-adaptive su-image-carousel-slides-style-default su-image-carousel-controls-style-dark su-image-carousel-align-center\" style=\"max-width:700px\" data-flickity-options='{\"groupCells\":true,\"cellSelector\":\".su-image-carousel-item\",\"adaptiveHeight\":true,\"cellAlign\":\"left\",\"prevNextButtons\":true,\"pageDots\":false,\"autoPlay\":false,\"imagesLoaded\":true,\"contain\":false,\"selectedAttraction\":1,\"friction\":1}' id=\"su_image_carousel_69d7dade26f94\"><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/baglamaacisi1.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"605\" height=\"444\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/baglamaacisi1.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/baglamaacisi2.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"605\" height=\"444\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/baglamaacisi2.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><\/div><script id=\"su_image_carousel_69d7dade26f94_script\">if(window.SUImageCarousel){setTimeout(function() {window.SUImageCarousel.initGallery(document.getElementById(\"su_image_carousel_69d7dade26f94\"))}, 0);}var su_image_carousel_69d7dade26f94_script=document.getElementById(\"su_image_carousel_69d7dade26f94_script\");if(su_image_carousel_69d7dade26f94_script){su_image_carousel_69d7dade26f94_script.parentNode.removeChild(su_image_carousel_69d7dade26f94_script);}<\/script><\/p>\n<p>Ba\u011flama a\u00e7\u0131s\u0131 kam d\u00f6nme a\u00e7\u0131s\u0131na ba\u011fl\u0131 olacakt\u0131r. Ba\u011flama a\u00e7\u0131s\u0131n\u0131n tam de\u011ferinin elde edilebilmesi i\u00e7in temel daire yar\u0131\u00e7ap\u0131 ve hareket e\u011frisinin tam olarak bilinmesi ile m\u00fcmk\u00fcnd\u00fcr. Ancak yakla\u015f\u0131k olarak \u015fekilde g\u00f6sterilen santrik toparlakl\u0131 \u00f6teleme yapan izleyici i\u00e7in h\u0131z analizi yap\u0131ld\u0131\u011f\u0131nda:<\/p>\n<p style=\"padding-left: 40px\"><strong>V<\/strong><sub>B3<\/sub>\u00a0= <strong>V<\/strong><sub>B2<\/sub>\u00a0+ <strong>V<\/strong><sub>B3\/B2<\/sub><\/p>\n<p>dir. Bu denklemde:<\/p>\n<p style=\"padding-left: 40px\">V<sub>B3<\/sub> = ds\/dt : \u0130zleyici h\u0131z\u0131<\/p>\n<p style=\"padding-left: 40px\">V<sub>B2<\/sub> : kam \u00fczerinde B noktas\u0131 h\u0131z\u0131 = r\u03c9 (r = |OB|)<\/p>\n<p>olup santrik izleyici i\u00e7in\u00a0<b>V<sub>B2<\/sub><\/b>\u00a0izleyici eksenine dik,\u00a0<b>V<sub>B3<\/sub><\/b> ise izleyici y\u00f6n\u00fcnde olacakt\u0131r. Bu durumda:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\tan \\text{\u03bc}=\\frac{{{{\\text{V}}_{{\\text{B}2}}}}}{{{{\\text{V}}_{{\\text{B}3}}}}}=\\frac{{\\text{r\u03c9}}}{{\\text{ds\/dt}}}=\\frac{\\text{r}}{{\\text{ds\/d\u03b8}}} <\/span><\/p>\n<p>Ba\u011flama a\u00e7\u0131s\u0131n\u0131n en iyi durumu \u03bc = 90\u00b0 dir. En k\u00f6t\u00fc durumu ise tan\u03bc n\u00fcn en k\u00fc\u00e7\u00fck de\u011ferde oldu\u011fu durumdur. Bu durum ise:<\/p>\n<p style=\"padding-left: 40px\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\tan {{\\text{\u03bc}}_{{\\min }}}=\\frac{{{{\\text{r}}_{\\text{p}}}}}{{{{{\\left( {\\text{ds\/d\u03b8}} \\right)}}_{{\\max }}}}} <\/span><\/p>\n<p>r<sub>p<\/sub>\u00a0ba\u011flama a\u00e7\u0131s\u0131n\u0131n minimum oldu\u011funda toparlak merkezinin kam merkezinden uzakl\u0131\u011f\u0131d\u0131r. Basit e\u011friler i\u00e7in r<sub>p<\/sub>, ds\/d\u03b8\u00a0n\u0131n maximum oldu\u011fu nokta olan orta noktada OB uzakl\u0131\u011f\u0131 yani: r<sub>p<\/sub>\u00a0= r<sub>t<\/sub> + H\/2 + r<sub>r<\/sub>\u00a0olacakt\u0131r. Burada r<sub>t<\/sub>\u00a0temel daire yar\u0131\u00e7ap\u0131 ve r<sub>r<\/sub> toparlak yar\u0131\u00e7ap\u0131d\u0131r. hareket e\u011frisinin t\u00fcrevi al\u0131narak veya \u015fekilde verilen e\u011frilerden biri i\u00e7in, (ds\/d\u03b8)<sub>max<\/sub> = C<sub>v<\/sub>H\/\u03b2 olarak elde edilebilecektir.<\/p>\n<p>Minimum ba\u011flama a\u00e7\u0131s\u0131 h\u0131za etki eden y\u00fcklere ve uygulama alan\u0131na ba\u011fl\u0131 olarak tasar\u0131mc\u0131 taraf\u0131ndan belirlenmesi gereken bir de\u011ferdir. Genel olarak literat\u00fcrde:<\/p>\n<p style=\"padding-left: 40px\">E\u011fer kam h\u0131z\u0131 &lt; 30 devir\/dakika ise \u03bc<sub>min<\/sub> &gt; 45\u00b0<\/p>\n<p style=\"padding-left: 40px\">E\u011fer kam h\u0131z\u0131 &gt; 30 devir\/dakika ise \u03bc<sub>min<\/sub> &gt; 60\u00b0<\/p>\n<p>olmas\u0131 gerekti\u011fi s\u00f6ylenir.<\/p>\n<p><strong>\u00d6rnek 3:<\/strong><\/p>\n<p>\u00d6nceki \u00f6rnekde (\u00f6rnek 2) elde edilmi\u015f olan haraket e\u011frisi kullan\u0131larak elde edilecek kamda uygulamadan dolay\u0131 minimum ba\u011flama a\u00e7\u0131s\u0131 \u03bc<sub>min<\/sub> &gt; 64\u00b0 olmas\u0131 isteniyor ise temel daire yar\u0131\u00e7ap\u0131n\u0131 bulunuz.<\/p>\n<p>Y\u00fckseli\u015f sikloidal hareket oldu\u011funa g\u00f6re \u015eekilden C<sub>v<\/sub> = 2 dir. Bu durumda:<\/p>\n<p style=\"padding-left: 40px\">(ds\/d\u03b8)<sub>max<\/sub> = C<sub>v<\/sub>H\/\u03b2 = 2(40)\/(2\u03c0\/3) = 120\/\u03c0 = 38.20<\/p>\n<p>olacakt\u0131r. Bu durumda:<\/p>\n<p style=\"padding-left: 40px\">r<sub>p<\/sub> = tan\u03bc<sub>min<\/sub> = 38.20 tan64\u00b0\u00a0= 78.32 mm<\/p>\n<p>dir. r<sub>p<\/sub>\u00a0= r<sub>t<\/sub> + H\/2 + r<sub>r<\/sub>\u00a0oldu\u011fundan r<sub>t\u00a0+ <\/sub>r<sub>r<\/sub> = 58.32 mm dir. r<sub>r<\/sub>\u00a0= 10 mm lik bir toparlak yar\u0131\u00e7ap\u0131 d\u00fc\u015f\u00fcn\u00fcld\u00fc\u011f\u00fcnde r<sub>t<\/sub> = 50 mm al\u0131nmas\u0131 uygundur (minimum ba\u011flama a\u00e7\u0131s\u0131 64\u00b0 ten b\u00fcy\u00fckt\u00fcr).<\/p>\n<h1><strong data-rich-text-format-boundary=\"true\">Kam Profili E\u011frili\u011fi<\/strong><\/h1>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-477\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img3-3.gif\" alt=\"\" width=\"400\" height=\"341\" \/><\/p>\n<p>Uygulamada toparlakl\u0131 izleyiciler i\u00e7in ba\u011flama a\u00e7\u0131s\u0131 kam boyutunu belirlemek i\u00e7in al\u0131nan temel kriterdir. Ancak baz\u0131 durumlarda ve bilhassa d\u00fcz y\u00fczeyli kamlarda, ba\u011flama a\u00e7\u0131s\u0131 kam boyutu belirlemede kullan\u0131lamaz. Bu durumlarda g\u00f6z \u00f6n\u00fcne al\u0131nmas\u0131 gereken kam profilinin e\u011frilik yar\u0131\u00e7ap\u0131d\u0131r. Grafik olarak kam profili elde edilirken, ilk olarak toparlak merkezi verilen hareket diyagram\u0131na g\u00f6re belirlendikten sonra, toparlak daireleri \u00e7izilir ve kam profili bu dairelere te\u011fet e\u011fri olarak elde edilir. Ancak yukar\u0131da g\u00f6sterildi\u011fi gibi, toparla\u011f\u0131n A,B,C,D ve E konumlar\u0131 g\u00f6z \u00f6n\u00fcne al\u0131nd\u0131\u011f\u0131nda, Bu dairelerin t\u00fcm\u00fcne te\u011fet bir e\u011fri \u00e7izmek m\u00fcmk\u00fcn olamamaktad\u0131r. Profil #1, profil e\u011frisi B ve D dairelerine te\u011fet olamad\u0131\u011f\u0131ndan bu konumlara eri\u015filemeyecektir. Profil #2 de ise, toparla\u011f\u0131n C ve E konumlar\u0131na eri\u015filmesi s\u00f6z konusu de\u011fildir. Verilen hareket e\u011frisini elde edebilmek i\u00e7in toparlak yar\u0131\u00e7ap\u0131n\u0131n k\u00fc\u00e7\u00fclt\u00fclmesi, temel daire yar\u0131\u00e7ap\u0131n\u0131n ise b\u00fcy\u00fclt\u00fclmesi gereklidir.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-478\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img4-3.gif\" alt=\"\" width=\"717\" height=\"452\" \/><\/p>\n<p>Yukar\u0131daki \u015fekil de ise, benzer durum d\u00fcz y\u00fczeyli izleyici i\u00e7in g\u00f6sterilmi\u015ftir.<\/p>\n<p>Yukar\u0131da g\u00f6sterilmi\u015f olan hareket e\u011frisinin elde edilemedi\u011fi durumlar ve keskin kam profili e\u011frilerinden ka\u00e7\u0131nmak i\u00e7in:<\/p>\n<p style=\"padding-left: 40px\">a.\u00a0 \u00a0 Temel dairesi yar\u0131 \u00e7ap\u0131 b\u00fcy\u00fclt\u00fclebilir<\/p>\n<p style=\"padding-left: 40px\">b.\u00a0 \u00a0 Daha k\u00fc\u00e7\u00fck \u00e7apta toparlak kullan\u0131labilir<\/p>\n<p style=\"padding-left: 40px\">c.\u00a0 \u00a0 D\u0131\u015f kam yerine i\u00e7 kam kullan\u0131labilir<\/p>\n<p>Genel olarak ba\u011flama a\u00e7\u0131s\u0131na g\u00f6re belirlenmi\u015f olan kam boyutu, kam\u0131n kullan\u0131laca\u011f\u0131 hacmin m\u00fcsaade edece\u011fi s\u0131n\u0131rlar i\u00e7inde belirli bir miktar b\u00fcy\u00fclt\u00fclmelidir.<\/p>\n<p>Bu \u015fekilde belirlenen kam temel daire \u00e7ap\u0131na g\u00f6re elde edilen kam profili sonu\u00e7ta mutlaka kontrol edilmeli, gerekli g\u00f6r\u00fcld\u00fc\u011f\u00fc durumlarda farkl\u0131 \u00e7\u00f6z\u00fcmlere gidilmelidir.<\/p>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div>\n\n\n<p><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-3\/\" data-type=\"page\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-16\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/back_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/\" data-type=\"page\" data-id=\"52\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-17\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/contents_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/\" data-type=\"page\" data-id=\"47\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-18\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/home_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-5\/\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-20\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/next_button.gif\" alt=\"\" \/><\/a><img loading=\"lazy\" decoding=\"async\" width=\"119\" height=\"40\" class=\"wp-image-15\" style=\"width: 119px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/ceres.gif\" alt=\"\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>8.4 Kam Boyutu Belirleme Amac\u0131m\u0131z elde etti\u011fimiz hareket e\u011frisini verecek bir kam profilini elde etmektir. Ayn\u0131 hareket e\u011frisini verecek farkl\u0131 boyutlarda kam imal edilebilir. Kam boyutlar\u0131n\u0131 kar\u015f\u0131la\u015ft\u0131rmak i\u00e7in temel daire \u00e7ap\u0131 esas al\u0131nacakt\u0131r. Uygulamalarda kam boyutunu m\u00fcmk\u00fcn oldu\u011funca k\u00fc\u00e7\u00fck almak &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-4\/\"> <span class=\"screen-reader-text\">8-4<\/span> Devam\u0131n\u0131 Oku &raquo;<\/a><\/p>\n","protected":false},"author":7747,"featured_media":0,"parent":371,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":"","_links_to":"","_links_to_target":""},"class_list":["post-465","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/465","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/users\/7747"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/comments?post=465"}],"version-history":[{"count":0,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/465\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/371"}],"wp:attachment":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/media?parent=465"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}