{"id":458,"date":"2021-09-04T15:55:50","date_gmt":"2021-09-04T15:55:50","guid":{"rendered":"https:\/\/blog.metu.edu.tr\/eresmech\/?page_id=458"},"modified":"2021-10-05T19:48:51","modified_gmt":"2021-10-05T19:48:51","slug":"haregnor","status":"publish","type":"page","link":"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch8\/8-3\/haregnor\/","title":{"rendered":"harEgNor"},"content":{"rendered":"
\n
\n\t

Hareket e\u011frilerinin “Normalizasyonu”<\/strong><\/h1>\n

Yukar\u0131da verilen e\u011frileri birbirleri ile kar\u015f\u0131la\u015ft\u0131rmak i\u00e7in bu e\u011frilerin “normalize” edilmesi gerekmektedir. Normalizasyon hareket denklemlerinde H, \u03c9 ve \u03b2 de\u011ferlerinin<\/p>\n

\u03c9 = 1 rad\/s<\/p>\n

H = 1 birim<\/p>\n

\u03b2 = 1 radyan<\/p>\n

olarak al\u0131nmas\u0131 ile yap\u0131l\u0131r. Kar\u015f\u0131la\u015ft\u0131rmak i\u00e7in \u015fekilde \u00e7e\u015fitli e\u011frilerin h\u0131z, ivme ve ivme de\u011fi\u015fim diyagramlar\u0131 g\u00f6sterilmi\u015ftir. Cv<\/sub>, Ca<\/sub>\u00a0ve Cj<\/sub>, normalize edilmi\u015f hareket e\u011frilerinin maksimum h\u0131z, ivme ve ivme de\u011fi\u015fim de\u011ferleridir. Her hangi H, \u03c9 ve \u03b2\u00a0de\u011feri i\u00e7in maximum h\u0131z, ivme ve ivme de\u011fi\u015fim de\u011feri (sadme) bulunmak istendi\u011finde:<\/p>\n

vmax<\/sub> = Cv<\/sub>H\u03c9\/\u03b2<\/p>\n

amax<\/sub> = Ca<\/sub>H\u03c92<\/sup>\/\u03b22<\/sup><\/p>\n

jmax<\/sub> = Cj<\/sub>H\u03c93<\/sup>\/\u03b23<\/sup><\/p>\n

olarak elde edilir. Her hangi bir H y\u00fckselme ve b kam d\u00f6nme hareketi i\u00e7in yazmak istedi\u011fimizde, normalize edilmi\u015f e\u011fri denklemini H ile \u00e7arpmak ve \u03b8 a\u00e7\u0131s\u0131 yerine \u03b8\/\u03b2 yerle\u015ftirmek yeterlidir. \u00d6rne\u011fin normalize edilmi\u015f \u00fc\u00e7\u00fcnc\u00fc derece hareket e\u011frisi (#2):<\/p>\n

s = 3\u03b82<\/sup> + 2\u03b82<\/sup><\/p>\n

olarak verildi\u011finden, denklemi H ile \u00e7arpar \u03b8 a\u00e7\u0131s\u0131 yerine \u03b8\/\u03b2 yerle\u015ftirir isek:<\/p>\n

s = H[3(\u03b8\/\u03b2)2<\/sup> \u2212 2(\u03b8\/\u03b2)3<\/sup>]\n

veya<\/p>\n

s = H(\u03b8\/\u03b2)2<\/sup>(3 \u2212 2\u03b8\/\u03b2)<\/p>\n

olacakt\u0131r. Bu e\u011frinin maksimum h\u0131z ve ivme de\u011ferleri: vmax<\/sub> = 1.5H\u03c9\/\u03b2, amax<\/sub> = 6H(\u03c9\/\u03b2)2<\/sup> dir.<\/p>\n

\"\"<\/p>\n

\u03b8 = 0 dan ba\u015flayan ve \u03b8 = \u03b2 da s = H kadar y\u00fckselen bu e\u011friler, merkez de\u011fi\u015ftirme ve H y\u00fcksekli\u011finden \u00e7\u0131karma yap\u0131larak geri d\u00f6n\u00fc\u015f e\u011frisi olarak da kullan\u0131labilir. Bu i\u015flemler \u015fekilde g\u00f6sterilmektedir. \u00d6rne\u011fin e\u011frinin \u03b8 = \u03b3 a\u00e7\u0131s\u0131nda y\u00fckselmeye ba\u015flamas\u0131 i\u00e7in e\u011fri denkleminde her q terimi yerine (\u03b8 \u2212 \u03b3) terimi yerle\u015ftirebilir, bu e\u011friyi geri d\u00f6n\u00fc\u015f e\u011frisi yapmak i\u00e7in ise, bu y\u00fckseli\u015f e\u011frisi denklemini (s(\u03b8)), H de\u011ferinden \u00e7\u0131karmak gereklidir. f(\u03b8) = H \u2212 s(\u03b8) denklemi \u03b8 = 0 da ba\u015flayan geri d\u00f6n\u00fc\u015f denklemidir. f(\u03b8) = H \u2212 s(\u03b8 \u2212 \u03b3) ise \u03b8 = \u03b3 da ba\u015flayan geri d\u00f6n\u00fc\u015f denklemi olur ). \u00c7ift harmonik d\u0131\u015f\u0131nda t\u00fcm e\u011friler simetrik oldu\u011fundan elde edilen e\u011friler yine istenilen \u00f6zelliklere sahip olacakt\u0131r.<\/p>\n

\"\"<\/p>\n

\"\"<\/h2>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div>\n\n\n

\"\"<\/a>\"\"<\/a>\"\"<\/a>\"\"<\/p>\n","protected":false},"excerpt":{"rendered":"

Hareket e\u011frilerinin “Normalizasyonu” Yukar\u0131da verilen e\u011frileri birbirleri ile kar\u015f\u0131la\u015ft\u0131rmak i\u00e7in bu e\u011frilerin “normalize” edilmesi gerekmektedir. Normalizasyon hareket denklemlerinde H, \u03c9 ve \u03b2 de\u011ferlerinin \u03c9 = 1 rad\/s H = 1 birim \u03b2 = 1 radyan olarak al\u0131nmas\u0131 ile yap\u0131l\u0131r. Kar\u015f\u0131la\u015ft\u0131rmak …<\/p>\n

harEgNor<\/span> Devam\u0131n\u0131 Oku »<\/a><\/p>\n","protected":false},"author":7747,"featured_media":0,"parent":405,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":"","_links_to":"","_links_to_target":""},"class_list":["post-458","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/458","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/users\/7747"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/comments?post=458"}],"version-history":[{"count":0,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/458\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/405"}],"wp:attachment":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/media?parent=458"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}