{"id":2216,"date":"2022-03-15T17:26:07","date_gmt":"2022-03-15T17:26:07","guid":{"rendered":"https:\/\/blog.metu.edu.tr\/eresmech\/?page_id=2216"},"modified":"2022-03-22T19:26:32","modified_gmt":"2022-03-22T19:26:32","slug":"6-1","status":"publish","type":"page","link":"https:\/\/blog.metu.edu.tr\/eresmech\/mechanisms\/ch6\/6-1\/","title":{"rendered":"6-1"},"content":{"rendered":"<div id=\"pl-gb2216-69d7910deed12\"  class=\"panel-layout\" ><div id=\"pg-gb2216-69d7910deed12-0\"  class=\"panel-grid panel-no-style\" ><div id=\"pgc-gb2216-69d7910deed12-0-0\"  class=\"panel-grid-cell\" ><div id=\"panel-gb2216-69d7910deed12-0-0-0\" class=\"so-panel widget widget_sow-editor panel-first-child panel-last-child widgetopts-SO\" data-index=\"0\" ><div\n\t\t\t\n\t\t\tclass=\"so-widget-sow-editor so-widget-sow-editor-base\"\n\t\t\t\n\t\t>\n<div class=\"siteorigin-widget-tinymce textwidget\">\n\t<h4><\/h4>\n<h4 class=\"has-text-color\"><span style=\"color: #ff0000\"><strong>&#8220;Solving problems is a practical art, like swimming or skiing, or playing piano: you can learn it only by imitation and practice. This book cannot offer you a magic key that opens all the doors and solves all the problems, but it offers you good examples for imitation and many opportunities for practice: if you wish to learn swimming you have to go into the water and if you wish to become a problem solver you have to solve problems &#8220;<\/strong><\/span><\/h4>\n<h4 class=\"has-text-color\" style=\"text-align: right\"><span style=\"color: #ff0000\"><strong>George Polya, Mathematical Discovery<\/strong><\/span><\/h4>\n<h1><span style=\"font-family: Arial, Helvetica, sans-serif\"><span style=\"color: #cc0000\">FORCE ANALYSIS IN MACHINERY<\/span><\/span><\/h1>\n<p>Mechanisms, which have been designed to meet certain kinematic specifications, may not function properly when used as a part of a machine. It may jam due to friction, the forces acting on the links may be too high or, in case of high speeds, intolerable inertia forces may result. Except the transmission angle, these force effects are neglected in the kinematics of mechanisms.<\/p>\n<p>A mechanism is specifically designed to transmit force and motion. After the determination of motion in a mechanism, one is involved with the physical shapes of each link and of each joint. The designs of these machine elements are mainly governed by the forces acting on them. The forces acting on the links and on the joints must be determined for such a design. High forces acting on the links will result with large link size and weight. Heavy links will in turn create large inertia forces. Thus, during this phase of the design, a mechanism that has perfect motion characteristics may be completely disregarded due to intolerable forces.<\/p>\n<p>Machines also consist of elastic members, such as springs, within their structure. Furthermore, due to the motion of the links, the forces acting on the members do not have constant magnitude and direction. These forces, coupled with the elasticity of the members, will result with an oscillatory motion, which was completely disregarded in previous sections. The assumption of rigidity will still be used in the force analysis for the bodies involved. However, we shall include specific elastic members, such as springs within the machine structure.<\/p>\n<h1><span style=\"font-family: Arial, Helvetica, sans-serif\"><span style=\"color: #cc0000\"><strong>6.1 PRINCIPLES OF DYNAMICS<\/strong><\/span><\/span><\/h1>\n<p>Fundamental principles of dynamics are\u00a0<strong><span style=\"color: #ff0000\">Newton&#8217;s Laws of Motion<\/span><\/strong>. These can be stated as follows:<\/p>\n<p>1. A body will remain in a state of rest, or of uniform motion in a straight line unless it is acted by external forces to change its state.<\/p>\n<p>2. The rate of change of the momentum of a body acted upon by an external force (or forces) is proportional to the resultant external force <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{F}} <\/span> and in the direction of that force:<\/p>\n<p style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{F}}=\\frac{{\\text{d}}\\left({\\text{m}}\\vec{\\text{v}}\\right)}{{\\text{dt}}} <\/span><\/p>\n<p>where m is the mass and <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{v}} <\/span> is the velocity of the center of mass of the body. For constant mass:<\/p>\n<p style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{F}}={\\text{m}}\\vec{\\text{a}} <\/span><\/p>\n<p>where <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{a}} <\/span> is the acceleration of the center of mass of the body.<\/p>\n<p>3. To every action of a force there is an equal and opposite reaction.<\/p>\n<p>These statements may be regarded as a definition or as an experimental fact. For ordinary sized bodies with velocities small compared to the speed of light, these statements have been the principles of dynamics and Newton&#8217;s laws of motion will be the main starting point for the force analysis. The basic quantities of dynamics are force, mass and time. Only intuitive definitions to these words can be given.<\/p>\n<p><em><strong><span style=\"color: #ff0000\">Force<\/span><\/strong><\/em>\u00a0can be defined in terms of Newton&#8217;s first law as an action that tends to change the motion of a body.The concept of a force can be made quantitative by defining it as a quantity that produces a unit acceleration of a standard body.<\/p>\n<p><strong><span style=\"color: #ff0000\"><em>Mass\u00a0<\/em><\/span><\/strong>of a body can be defined by using Newton&#8217;s second law as the ratio of the force acting on the body to the resulting acceleration.<\/p>\n<p><span style=\"color: #ff0000\"><strong><em>Time<\/em><\/strong><\/span>\u00a0is a concept for ordering the flow of events.<\/p>\n<p>We shall be using SI systems of units. A list of units relevant to the course is given below<\/p>\n<p><strong><span style=\"color: #ff0000\">SI System of units<\/span><\/strong><\/p>\n<p style=\"text-align: left\" align=\"center\"><strong><span style=\"color: #ff0000\"><u>Quantity<\/u>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<u>Name<\/u> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <u>Abbreviation<\/u><\/span><\/strong><\/p>\n<p style=\"text-align: left\" align=\"center\">Length\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 meter\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 m<br \/>\nMass\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0kilogram\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0kg<br \/>\nForce\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Newton\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 N<br \/>\nTime\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 second\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0s<br \/>\nWork\/Energy\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Joule\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 J<br \/>\nPower\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Watt\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 W<br \/>\nFrequency\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Hertz\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Hz<\/p>\n<p><em><strong>The following important relationships are effective in working with SI units<\/strong><\/em>:<\/p>\n<p><strong><span style=\"color: #ff0000\"> \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a01 N = 1 kg m\/s<sup>2<\/sup><br \/>\n<\/span><\/strong><\/p>\n<p><strong><span style=\"color: #ff0000\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a01 J = 1 N\u00b7m<br \/>\n<\/span><\/strong><\/p>\n<p><strong><span style=\"color: #ff0000\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a01 W = 1 J\/s<\/span><\/strong><\/p>\n<h1><span style=\"font-family: Arial, Helvetica, sans-serif\"><span style=\"color: #cc0000\"><strong>6.1.1 FORCES AND COUPLES<\/strong><\/span><\/span><\/h1>\n<p><strong><em><span style=\"color: #ff0000\">Force<\/span><\/em><\/strong>\u00a0is a<span style=\"color: #ff0000\">\u00a0<em><u>vectorial quantity<\/u><\/em>\u00a0<\/span>that has <em><u><span style=\"color: #ff0000\">magnitude<\/span><\/u><\/em>, <em><span style=\"color: #ff0000\"><u>direction<\/u><\/span><u><\/u><\/em>\u00a0and\u00a0<em><u><span style=\"color: #ff0000\">line of application<\/span><\/u><\/em>. It can be treated as any other vector quantity. If the equilibrium of the rigid body is our only concern, the point of application of a force is not important. Note, that this will not be correct when the internal stress of a rigid body is considered or when the body under consideration is not rigid.<\/p>\n<p>A force in space can be represented by using unit vectors directed along the co-ordinate axes of an arbitrary rectangular reference frame. A unit vector in the direction and sense of the force can also represent it.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2709\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image001-3.gif\" alt=\"\" width=\"811\" height=\"238\" \/><\/p>\n<p>Different forms of representing a planar force are shown below.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2710\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image002-3.gif\" alt=\"\" width=\"792\" height=\"510\" \/><\/p>\n<p>Addition and subtraction of concurrent forces (forces whose lines of action intersect at one point) obey the\u00a0<span style=\"color: #ff0000\"><strong>parallelogram law of addition<\/strong><\/span> that is schematically shown below. The addition can be carried out graphically by placing the force vectors one after the other in head-to-tail fashion, in which case half of the parallelogram is drawn.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-2711 aligncenter\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image003-4.gif\" alt=\"\" width=\"763\" height=\"260\" \/><\/p>\n<p>For a system of concurrent forces, the parallelogram law of addition can be applied for the forces in pairs. Alternatively the resultant of the system of forces can be determined using a<span style=\"color: #ff0000\"><strong>\u00a0force polygon<\/strong><\/span>\u00a0. If all the forces lie in a plane, then the resulting force polygon is also plane; otherwise a spatial force polygon will result. The parallelogram law of addition results with the addition of the components of the forces along the axes:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2712\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image004-3.gif\" alt=\"\" width=\"793\" height=\"348\" \/><\/p>\n<p>If there are two equal and opposite forces whose lines of action are parallel to each other, the resultant of these two forces is known as a <span style=\"color: #ff0000\"><strong>couple<\/strong><\/span>.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2713\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image005-3.gif\" alt=\"\" width=\"527\" height=\"218\" \/>The arm of a couple is defined as the perpendicular distance, h, between the two lines of action. The\u00a0<span style=\"color: #ff0000\"><strong>moment of the couple<\/strong><\/span> is another vector <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{M}} <\/span>\u00a0that is normal to the plane of the couple and is in accordance with the right-hand rule. The magnitude of the moment is given by the product: M = hF. The moment vector can be determined by the vectorial product: (<span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{M}}=\\vec{\\text{r}}{\\text{\u00d7}}\\vec{\\text{F}} <\/span>), where <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{r}} <\/span> is the position vector from a point on the line of action of <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{F}} <\/span> to another point on the line of action of <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{F}} <\/span>. Note that:<\/p>\n<p><span style=\"color: #ff0000\"><strong>a) The moment vector does not have a point of application. Hence, it is a free vector.<\/strong><\/span><\/p>\n<p><strong><span style=\"color: #ff0000\">\u00a0b) The relative position vector, <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{r}} <\/span>, is in between any two points on the lines of action of the forces forming the couple.<\/span><\/strong><\/p>\n<p><strong><span style=\"color: #ff0000\">c) The force couple that creates a moment, <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{M}} <\/span>, is not unique, e.g. there are other force couples that may create the same moment.<\/span><\/strong><\/p>\n<p>We also define the moment of a force about an arbitrary point with the vectorial product:<\/p>\n<p style=\"text-align: center\"><span style=\"color: #000000\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{M}}=\\vec{\\text{r}}{\\text{\u00d7}}\\vec{\\text{F}} <\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2714\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image006-3.gif\" alt=\"\" width=\"457\" height=\"188\" \/><\/p>\n<p>In case of nonconcurrent force systems, the system of forces can be reduced to a force acting at an arbitrary point and a moment.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2715 size-full\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image008-3.gif\" alt=\"\" width=\"1056\" height=\"268\" \/><\/p>\n<p>The resultant force and moment are given by the equations<\/p>\n<p style=\"text-align: center\"><span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{F}}=\\sum\\limits_{\\text{i}}{{{{{\\vec{\\text{F}}}}_{\\text{i}}}}}<\/span><\/span><\/p>\n<p style=\"text-align: center\"><span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{M}}=\\sum\\limits_{\\text{i}}{\\left(\\vec{{\\text{r}}_{\\text{i}}}{\\text{\u00d7}}\\vec{{\\text{F}}_{\\text{i}}}\\right)}<\/span><\/span><\/p>\n<p>The resultant force, <span style=\"color: #000000\"> <span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{F}} <\/span><\/span>, is as if the forces were concurrent at a point. However, there is also a moment <span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{M}} <\/span><\/span> acting at the particular point considered. The system of forces can further be reduced to a single force, <span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{R}} <\/span><\/span>, provided that the moment of this force about an arbitrary point is equal to the moment of the system of forces, e.g. A, where <span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{r}} <\/span><\/span> and <span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{{\\text{r}}_{\\text{i}}} <\/span><\/span><strong>\u00a0<\/strong>are the position vectors of the resultant and the forces from an arbitrary point A.<\/p>\n<p>The magnitude and direction of <span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{R}} <\/span><\/span>\u00a0can be determined from the force polygon as if all of the forces were concurrent.<\/p>\n<p style=\"text-align: center\"><span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{R}}=\\sum\\limits_{\\text{i}}{{{{{\\vec{\\text{F}}}}_{\\text{i}}}}}<\/span><\/span><\/p>\n<p style=\"text-align: center\"><span style=\"color: #000000\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\vec{\\text{r}}{\\text{\u00d7}}\\vec{\\text{R}}=\\vec{\\text{M}}=\\sum\\limits_{\\text{i}}{\\left(\\vec{{\\text{r}}_{\\text{i}}}{\\text{\u00d7}}\\vec{{\\text{F}}_{\\text{i}}}\\right)}<\/span><\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2716\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2022\/03\/image009-3.gif\" alt=\"\" width=\"940\" height=\"280\" \/><\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div>\n\n\n<p> <a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mechanisms\/ch6\/\" data-type=\"page\" data-id=\"52\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-16\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/back_button.gif\" alt=\"\" \/><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-17\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/contents_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mechanisms\/\" data-type=\"page\" data-id=\"47\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-18\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/home_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mechanisms\/ch6\/6-1-2\/\" data-type=\"page\" data-id=\"92\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-20\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/next_button.gif\" alt=\"\" \/><\/a><img loading=\"lazy\" decoding=\"async\" width=\"119\" height=\"40\" class=\"wp-image-15\" style=\"width: 119px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/ceres.gif\" alt=\"\" \/> <\/p>\n","protected":false},"excerpt":{"rendered":"<p>&#8220;Solving problems is a practical art, like swimming or skiing, or playing piano: you can learn it only by imitation and practice. This book cannot offer you a magic key that opens all the doors and solves all the problems, &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mechanisms\/ch6\/6-1\/\"> <span class=\"screen-reader-text\">6-1<\/span> Devam\u0131n\u0131 Oku &raquo;<\/a><\/p>\n","protected":false},"author":7747,"featured_media":0,"parent":1982,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"full-width-page.php","meta":{"footnotes":"","_links_to":"","_links_to_target":""},"class_list":["post-2216","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/2216","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/users\/7747"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/comments?post=2216"}],"version-history":[{"count":0,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/2216\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/1982"}],"wp:attachment":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/media?parent=2216"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}