{"id":1493,"date":"2021-09-11T19:38:22","date_gmt":"2021-09-11T19:38:22","guid":{"rendered":"https:\/\/blog.metu.edu.tr\/eresmech\/?page_id=1493"},"modified":"2022-03-12T23:24:04","modified_gmt":"2022-03-12T23:24:04","slug":"3-4_bds","status":"publish","type":"page","link":"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch3\/3-4\/3-4_bds\/","title":{"rendered":"3-4_bds"},"content":{"rendered":"<div id=\"pl-gb1493-69d746bcc7f9d\"  class=\"panel-layout\" ><div id=\"pg-gb1493-69d746bcc7f9d-0\"  class=\"panel-grid panel-no-style\" ><div id=\"pgc-gb1493-69d746bcc7f9d-0-0\"  class=\"panel-grid-cell\" ><div id=\"panel-gb1493-69d746bcc7f9d-0-0-0\" class=\"so-panel widget widget_sow-editor panel-first-child panel-last-child widgetopts-SO\" data-index=\"0\" ><div\n\t\t\t\n\t\t\tclass=\"so-widget-sow-editor so-widget-sow-editor-base\"\n\t\t\t\n\t\t>\n<div class=\"siteorigin-widget-tinymce textwidget\">\n\t<h1><strong data-rich-text-format-boundary=\"true\">Bir Mekanizmada Bulunan Ba\u011f\u0131ms\u0131z Devre Say\u0131s\u0131<\/strong><\/h1>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1495\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/image1-5.gif\" alt=\"\" width=\"346\" height=\"215\" \/><\/p>\n<p>Uzuv say\u0131s\u0131 <em>l<\/em> ve mafsal say\u0131s\u0131 j olan bir kinematik zinciri ele alal\u0131m. Yukar\u0131da 10 uzuvlu (<em>l<\/em> = 10) 12 mafsall\u0131 (j = 12) bir mekanizma g\u00f6r\u00fclmektedir.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1496\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/image2-5.gif\" alt=\"\" width=\"329\" height=\"211\" \/><\/p>\n<p>1-2 , 8-9 ve 1-7 numaral\u0131 uzuvlar aras\u0131nda bulunan mafsallar\u0131 s\u00f6kelim (isterseniz siz de\u011fi\u015fik mafsallar\u0131 s\u00f6k\u00fcn). S\u00f6kme s\u0131ras\u0131nda kural hi\u00e7 bir uzuv bo\u015fta (zincire ba\u011flanmam\u0131\u015f olarak) kalmayacak ve s\u00f6kme i\u015flemine mekanizmada devre kalmayana kadar (a\u00e7\u0131k kinematik zincir olu\u015fana kadar) edilecektir. S\u00f6k\u00fclen mafsallar de\u011fi\u015fik olabilir, ancak kinematik zinciri a\u00e7\u0131k hale getirmek, hi\u00e7 bir devre b\u0131rakmamak i\u00e7in s\u00f6k\u00fclmesi gereken mafsal say\u0131s\u0131 daima ayn\u0131 olacakt\u0131r.<\/p>\n<p>S\u00f6k\u00fclen mafsal say\u0131s\u0131 daima kinematik zincirde bulunan ba\u011f\u0131ms\u0131z devre say\u0131s\u0131na e\u015fittir. Ba\u011f\u0131ms\u0131z devre say\u0131s\u0131n\u0131 L ile g\u00f6sterelim. \u015eekilde g\u00f6sterilen mekanizma i\u00e7in L = 3 t\u00fcr. Elde edilen a\u00e7\u0131k kinematik zincirlerde uzuv say\u0131s\u0131 yine ba\u015flang\u0131\u00e7 zincirinde oldu\u011fu gibi <em>l<\/em> dir ancak kalan mafsal say\u0131s\u0131 uzuv say\u0131s\u0131ndan bir eksik (<em>l<\/em> \u2212 1) olacakt\u0131r. Yukar\u0131daki \u00f6rne\u011fimizde kalan mafsal say\u0131s\u0131 9 dur.<\/p>\n<p>Mafsal say\u0131s\u0131 j oldu\u011funa g\u00f6re:<\/p>\n<p style=\"padding-left: 40px;text-align: center\">j = A\u00e7\u0131k kinematik zincirde mafsal say\u0131s\u0131 + S\u00f6k\u00fclen mafsal say\u0131s\u0131 = <em>l<\/em> \u2212 1\u00a0+ L<\/p>\n<p>veya<\/p>\n<p style=\"text-align: center\">L\u00a0=\u00a0j \u2212\u00a0<em>l<\/em>\u00a0+\u00a01<\/p>\n<p>Bu basit fakat \u00e7ok \u00f6nemli denklem Euler taraf\u0131ndan bulunmu\u015ftur (Euler&#8217;in \u00e7oky\u00fczl\u00fc denkleminin d\u00fczleme indirgenmi\u015f hali) ve bir mekanizmada ba\u011f\u0131ms\u0131z devre kapal\u0131l\u0131k denklemi say\u0131s\u0131n\u0131 belirlemek i\u00e7in kullan\u0131labilir. Ancak bu, yazaca\u011f\u0131m\u0131z denklemlerin birbirlerinden ba\u011f\u0131ml\u0131 veya ba\u011f\u0131ms\u0131z olup olmad\u0131\u011f\u0131n\u0131 g\u00f6steremez. Bunu bizim kontrol etmemiz gereklidir (bir devre di\u011fer devrelerin toplam\u0131 veya fark\u0131 ile elde edilebiliyor ise, ba\u011f\u0131ml\u0131 devredir). Her devre i\u00e7in yaz\u0131lan vekt\u00f6r devre denklemi iki skaler denklemi olu\u015fturdu\u011fundan toplam 2L denklem elde edilir. Bu denklemlerde hareketin kinematik olarak belirli olmas\u0131 i\u00e7in 2L + F kadar konum parametresi bulunmal\u0131d\u0131r (F mekanizma serbestlik derecesidir).<\/p>\n<p style=\"padding-left: 40px\"><b><span style=\"color: #000066\">Not:<\/span><\/b><\/p>\n<p style=\"padding-left: 40px\"><span style=\"color: #000066\">1. Devre say\u0131s\u0131 mafsal tipine ba\u011fl\u0131 de\u011fildir.<\/span><\/p>\n<p style=\"padding-left: 40px\"><span style=\"color: #000066\">2. Devre say\u0131s\u0131 uzay serbestlik derecesine ba\u011fl\u0131 de\u011fildir.<\/span><\/p>\n<p style=\"padding-left: 40px\"><span style=\"color: #000066\">3. Devre say\u0131s\u0131 mekanizma serbestlik derecesine ba\u011fl\u0131 de\u011fildir.<\/span><\/p>\n<p style=\"text-align: left\"><strong>\u00d6rnek:<\/strong><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1497\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/image3-3.gif\" alt=\"\" width=\"327\" height=\"201\" \/><\/p>\n<p>Yukar\u0131da g\u00f6sterilmi\u015f olan kinematik zincirde ka\u00e7 ba\u011f\u0131ms\u0131z devre oldu\u011funu bulunuz.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1498\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/image4-2.gif\" alt=\"\" width=\"381\" height=\"216\" \/><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1499\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/image5-2.gif\" alt=\"\" width=\"369\" height=\"223\" \/><\/p>\n<p style=\"text-align: center\">L = 17 \u2212 14 + 1 = 4 adet ba\u011f\u0131ms\u0131z devre vard\u0131r.<\/p>\n<p><strong>\u00d6rnek:<\/strong><\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1500\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/image6-3.gif\" alt=\"\" width=\"366\" height=\"208\" \/><\/p>\n<p>Yukar\u0131da g\u00f6sterilmi\u015f olan kap\u0131 a\u00e7ma mekanizmas\u0131nda ka\u00e7 ba\u011f\u0131ms\u0131z devre oldu\u011funu bulunuz.<\/p>\n<p><em>l<\/em> = 15\u00a0 ve\u00a0 j = 19\u00a0 olup L = 20 \u2013 14 + 1 = 5 tir.<\/p>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div>\n\n\n<p>  <a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch3\/3-4\/\" data-type=\"page\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-16\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/back_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch3\/\" data-type=\"page\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-17\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/contents_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/\" data-type=\"page\" data-id=\"47\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-18\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/home_button.gif\" alt=\"\" \/><\/a><img loading=\"lazy\" decoding=\"async\" width=\"119\" height=\"40\" class=\"wp-image-15\" style=\"width: 119px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/ceres.gif\" alt=\"\" \/>       <\/p>\n","protected":false},"excerpt":{"rendered":"<p>Bir Mekanizmada Bulunan Ba\u011f\u0131ms\u0131z Devre Say\u0131s\u0131 Uzuv say\u0131s\u0131 l ve mafsal say\u0131s\u0131 j olan bir kinematik zinciri ele alal\u0131m. Yukar\u0131da 10 uzuvlu (l = 10) 12 mafsall\u0131 (j = 12) bir mekanizma g\u00f6r\u00fclmektedir. 1-2 , 8-9 ve 1-7 numaral\u0131 uzuvlar &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch3\/3-4\/3-4_bds\/\"> <span class=\"screen-reader-text\">3-4_bds<\/span> Devam\u0131n\u0131 Oku &raquo;<\/a><\/p>\n","protected":false},"author":7747,"featured_media":0,"parent":826,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":"","_links_to":"","_links_to_target":""},"class_list":["post-1493","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/1493","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/users\/7747"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/comments?post=1493"}],"version-history":[{"count":0,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/1493\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/826"}],"wp:attachment":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/media?parent=1493"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}