{"id":1039,"date":"2021-09-09T14:44:23","date_gmt":"2021-09-09T14:44:23","guid":{"rendered":"https:\/\/blog.metu.edu.tr\/eresmech\/?page_id=1039"},"modified":"2022-03-19T17:22:14","modified_gmt":"2022-03-19T17:22:14","slug":"eniyibagacisi","status":"publish","type":"page","link":"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch7\/7-1\/eniyibagacisi\/","title":{"rendered":"enIyiBagAcisi"},"content":{"rendered":"<div id=\"pl-gb1039-69d746b950612\"  class=\"panel-layout\" ><div id=\"pg-gb1039-69d746b950612-0\"  class=\"panel-grid panel-no-style\" ><div id=\"pgc-gb1039-69d746b950612-0-0\"  class=\"panel-grid-cell\" ><div id=\"panel-gb1039-69d746b950612-0-0-0\" class=\"so-panel widget widget_sow-editor panel-first-child panel-last-child widgetopts-SO\" data-index=\"0\" ><div\n\t\t\t\n\t\t\tclass=\"so-widget-sow-editor so-widget-sow-editor-base\"\n\t\t\t\n\t\t>\n<div class=\"siteorigin-widget-tinymce textwidget\">\n\t<h1><strong data-rich-text-format-boundary=\"true\">Ba\u011flama A\u00e7\u0131s\u0131 En \u0130yi Olan \u00c7ift Kol Mekanizmas\u0131 Tasar\u0131m\u0131<\/strong><\/h1>\n<p>\u00c7ift kol mekanizmas\u0131 genel olarak d\u00fczg\u00fcn bir d\u00f6nme hareketini d\u00fczg\u00fcn olmayan bir d\u00f6nme hareketine d\u00f6n\u00fc\u015ft\u00fcrmek i\u00e7in kullan\u0131l\u0131r. De\u011fi\u015fik hareket \u00f6zellikleri i\u00e7in bazen bir kol-sarka\u00e7 mekanizmas\u0131 ile birlikte kullan\u0131labilir (\u00f6rne\u011fin zaman oran\u0131n\u0131 art\u0131rmak i\u00e7in bir \u00e7ift-kol mekanizmas\u0131 ile bir kol-sarka\u00e7 mekanizmas\u0131n\u0131n seri ba\u011flanmas\u0131 ile elde edilen bir 6-\u00e7ubuk mekanizmas\u0131 kullan\u0131labilir). \u015eekilde \u00e7ift kol oranlar\u0131nda bir d\u00f6rt-\u00e7ubuk mekanizmas\u0131 g\u00f6r\u00fclmektedir. Ba\u011flama a\u00e7\u0131s\u0131n\u0131n 90\u00b0\u00a0den sapmas\u0131n\u0131n maksimum oldu\u011fu noktalar sabit uzuv ile giri\u015f kolu olan krank\u0131n ayn\u0131 do\u011frultuda oldu\u011fu konumlard\u0131r. Ba\u011flama a\u00e7\u0131s\u0131n\u0131n dik a\u00e7\u0131dan yapt\u0131\u011f\u0131 maksimum sapman\u0131n azalt\u0131labilmesi i\u00e7in bu iki sapma de\u011ferinin e\u015fit olmas\u0131 gerekir (\u03bc<sub>max<\/sub> \u2212 90\u00b0 = 90\u00b0 \u2212 \u03bc<sub>min<\/sub>).<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-1123\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img1-10.gif\" alt=\"\" width=\"637\" height=\"562\" \/><\/p>\n<p>Giri\u015f kolunun 180\u00b0 d\u00f6nmesine kar\u015f\u0131 \u00e7\u0131k\u0131\u015f kolu bir \u03c8 a\u00e7\u0131s\u0131 kadar d\u00f6necek (\u03c8\u00a0&lt; 180\u00b0 kabul edilecektir. Kalan ikinci 180\u00b0 giri\u015f kolu d\u00f6nmesi s\u0131ras\u0131nda \u00e7\u0131k\u0131\u015f kolu 360\u00b0 \u2212 \u03c8 kadar d\u00f6nmesi gerekmektedir). Ba\u011flama a\u00e7\u0131s\u0131n\u0131n en k\u00fc\u00e7\u00fck de\u011feri \u03bc<sub>min<\/sub>\u00a0olsun. \u0130ki s\u0131n\u0131r de\u011fer \u015fekilde g\u00f6r\u00fcld\u00fc\u011f\u00fc gibidir. Bu iki s\u0131n\u0131r konum i\u00e7in ba\u011flama a\u00e7\u0131lar\u0131n\u0131n dik a\u00e7\u0131dan sapmalar\u0131 e\u015fitlendikten sonra devre kapal\u0131l\u0131k denklemi yaz\u0131l\u0131r ise:<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\">\u2212a<sub>1<\/sub> \u2212 a<sub>2<\/sub> + a<sub>3<\/sub>e<sup>i(\u03c8<sub>1<\/sub> \u2212 \u03c0 + \u03bc<sub>min<\/sub>)<\/sup>\u00a0 = a<sub>4<\/sub>e<sup>i\u03c8<sub>1<\/sub><\/sup><\/td>\n<td style=\"text-align: right\">(1)<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center\">\u2212a<sub>1<\/sub> + a<sub>2<\/sub> + a<sub>3<\/sub>e<sup>i(\u03c8<sub>1<\/sub> + \u03c8 \u2212 \u03bc<sub>min<\/sub>)<\/sup> = a<sub>4<\/sub>e<sup>i(\u03c8<sub>1<\/sub> + \u03c8)<\/sup><\/td>\n<td style=\"text-align: right\">(2)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>elde edilir. Ayr\u0131ca bu maksimum ve minimum ba\u011flama a\u00e7\u0131s\u0131 de\u011ferlerinin birbirlerine e\u015fit olmas\u0131 \u015fart\u0131 kullan\u0131ld\u0131\u011f\u0131nda:<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\">a<sub>1<\/sub><sup>2<\/sup> + a<sub>2<\/sub><sup>2<\/sup> = a<sub>3<\/sub><sup>2<\/sup> + a<sub>4<\/sub><sup>2<\/sup><\/td>\n<td style=\"text-align: right\">(3)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>elde edilir. a<sub>1<\/sub> = 1 olarak al\u0131nd\u0131\u011f\u0131nda \u03bb = a<sub>4<\/sub>\/a<sub>3<\/sub> ve Z\u00a0= a<sub>3<\/sub>e<sup>i\u03c8<sub>1<\/sub><\/sup> i\u00e7in denklem (1) ve (2)<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\">\u22121\u00a0\u2212 a<sub>2<\/sub> \u2212 Ze<sup>i\u03bc<sub>min<\/sub><\/sup>\u00a0 = \u03bbZ<\/td>\n<td style=\"text-align: right\">(4)<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center\">\u22121\u00a0+ a<sub>2<\/sub> + Ze<sup>i(\u03c8 \u2212 \u03bc<sub>min<\/sub>)<\/sup> = \u03bbZe<sup>i\u03c8<\/sup><\/td>\n<td style=\"text-align: right\">(5)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"text-align: center\"><div class=\"su-image-carousel  su-image-carousel-has-spacing su-image-carousel-has-lightbox su-image-carousel-has-outline su-image-carousel-adaptive su-image-carousel-slides-style-default su-image-carousel-controls-style-dark su-image-carousel-align-center\" style=\"max-width:550px\" data-flickity-options='{\"groupCells\":true,\"cellSelector\":\".su-image-carousel-item\",\"adaptiveHeight\":true,\"cellAlign\":\"left\",\"prevNextButtons\":true,\"pageDots\":false,\"autoPlay\":false,\"imagesLoaded\":true,\"contain\":false,\"selectedAttraction\":1,\"friction\":1}' id=\"su_image_carousel_69d746b951ee6\"><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/ciftkol1.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"605\" height=\"440\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/ciftkol1.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><div class=\"su-image-carousel-item\"><div class=\"su-image-carousel-item-content\"><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/ciftkol23.gif\" target=\"_blank\" rel=\"noopener noreferrer\" data-caption=\"\"><img loading=\"lazy\" decoding=\"async\" width=\"605\" height=\"440\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/ciftkol23.gif\" class=\"\" alt=\"\" \/><\/a><\/div><\/div><\/div><script id=\"su_image_carousel_69d746b951ee6_script\">if(window.SUImageCarousel){setTimeout(function() {window.SUImageCarousel.initGallery(document.getElementById(\"su_image_carousel_69d746b951ee6\"))}, 0);}var su_image_carousel_69d746b951ee6_script=document.getElementById(\"su_image_carousel_69d746b951ee6_script\");if(su_image_carousel_69d746b951ee6_script){su_image_carousel_69d746b951ee6_script.parentNode.removeChild(su_image_carousel_69d746b951ee6_script);}<\/script><\/p>\n<p>olarak yaz\u0131labilir. Z parametresini (4) ve (5) denklemlerini kullanarak yok edersek<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle \\frac{{1+{{\\text{a}}_{2}}}}{{1-{{\\text{a}}_{2}}}}=\\frac{{\\text{\u03bb}+{{\\text{e}}^{{\\text{i}{{\\text{\u03bc}}_{{\\text{min}}}}}}}}}{{{{\\text{e}}^{{\\text{i\u03c8}}}}\\left( {\\text{\u03bb}-{{\\text{e}}^{{\\text{i}{{\\text{\u03bc}}_{{\\text{min}}}}}}}} \\right)}} <\/span><\/td>\n<td style=\"text-align: right\">(6)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>elde edilir. Bu denklem<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\">a<sub>2<\/sub>[\u03bbcos(\u03c8\/2) \u2212 i sin(\u03c8\/2 \u2212 \u03bc<sub>min<\/sub>)] + i \u03bbsin(\u03c8\/2) \u2212 cos(\u03c8\/2 \u2212 \u03bc<sub>min<\/sub>) = 0<\/td>\n<td style=\"text-align: right\">(7)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>olarak yaz\u0131labilir. Denklemin sanal ve reel k\u0131s\u0131mlar\u0131n\u0131 ayr\u0131 ayr\u0131 s\u0131f\u0131ra e\u015fitler, \u03bb\u00a0ve a<sub>2<\/sub>\u00a0i\u00e7in \u00e7\u00f6z\u00fcm yaparsak:<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {{\\text{\u03bb}}^{2}}=\\frac{{\\sin \\left( {\\text{\u03c8}-2{{\\text{\u03bc}}_{{\\text{min}}}}} \\right)}}{{\\sin \\left( \\text{\u03c8} \\right)}} <\/span><\/td>\n<td style=\"text-align: right\">(8)<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {{\\text{a}}_{2}}^{2}=\\frac{{\\tan \\left( {\\text{\u03c8}\/2} \\right)}}{{\\tan \\left( {\\text{\u03c8}\/2-{{\\text{\u03bc}}_{{\\text{min}}}}} \\right)}} <\/span><\/td>\n<td style=\"text-align: right\">(9)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>0&lt; \u03c8 &lt;180\u00b0 oldu\u011fundan sin\u03c8 &gt; 0 ve \u03bb<sup>2<\/sup>\u00a0&gt; 0 olacakt\u0131r ve \u03c8 \u2212\u00a02\u03bc<sub>min<\/sub> &gt; 0 veya \u03bc<sub>min<\/sub> &lt; \u03c8\/2 sonucu elde edilir. Farkl\u0131 bir deyi\u015f ile en k\u00fc\u00e7\u00fck ba\u011flama a\u00e7\u0131s\u0131 de\u011feri bir \u00e7ift kol mekanizmas\u0131 i\u00e7in \u03c8\/2 den daha iyi olamaz. E\u011fer \u03c8 a\u00e7\u0131s\u0131 k\u00fc\u00e7\u00fcl\u00fcr ise, ba\u011flama a\u00e7\u0131s\u0131n\u0131n 90\u00b0 den sapmas\u0131 artacakt\u0131r (\u03bb = 1 iken mekanizma katlanabilir bir konuma sahiptir, yani en k\u0131sa uzuv boyu ile en uzun uzuv boyu toplam\u0131 di\u011fer iki uzuv boyu toplam\u0131na e\u015fittir).<\/p>\n<p><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {\\text{a}_{3}}^{2}=\\text{Z}\\bar{\\text{Z}} <\/span> oldu\u011fundan a<sub>3<\/sub> uzuv boyutu:<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {{\\text{a}}_{3}}^{2}=\\frac{{{{{\\left( {{{\\text{a}}_{2}}+1} \\right)}}^{2}}}}{{\\left( {\\text{\u03bb}+{{\\text{e}}^{{\\text{i}{{\\text{\u03bc}}_{{\\text{min}}}}}}}} \\right)\\left( {\\text{\u03bb}+{{\\text{e}}^{{\\text{-i}{{\\text{\u03bc}}_{{\\text{min}}}}}}}} \\right)}} <\/span><\/td>\n<td style=\"text-align: right\">(7)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>(8) ve (9) numaral\u0131 denklemlerden a<sub>2<\/sub> ve \u03bb de\u011ferleri kullan\u0131l\u0131r ise:<\/p>\n<table border=\"0\" width=\"100%\">\n<tbody>\n<tr>\n<td style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {{\\text{a}}_{3}}^{2}=\\frac{{\\sin \\left( \\text{\u03c8} \\right)}}{{\\sin \\left( {2{{\\text{\u03bc}}_{{\\text{min}}}}} \\right)}}\\left[ {\\frac{{\\tan \\left( {\\text{\u03c8}\/2} \\right)}}{{\\tan \\left( {\\text{\u03c8}\/2-{{\\text{\u03bc}}_{{\\text{min}}}}} \\right)}}-1} \\right]=\\frac{{\\sin \\left( \\text{\u03c8} \\right)}}{{\\sin \\left( {2{{\\text{\u03bc}}_{{\\text{min}}}}} \\right)}}\\left( {{{\\text{a}}_{2}}^{2}-1} \\right) <\/span><\/td>\n<td style=\"text-align: right\">(11)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Ayr\u0131ca a<sub>4<\/sub> = \u03bba<sub>3<\/sub> t\u00fcr. Elde edilen sonu\u00e7 mekanizma mutlaka Grashof kural\u0131na g\u00f6re kontrol edilmelidir.<\/p>\n<p><strong>\u00d6rnek:<\/strong><\/p>\n<p>\u00c7ift- kol oran\u0131nda bir d\u00f6rt-\u00e7ubuk mekanizmas\u0131nda krank\u0131n ilk yar\u0131m tur d\u00f6n\u00fc\u015f\u00fcnde \u00e7\u0131k\u0131\u015f kolunun 150\u00b0\u00a0d\u00f6nmesi istenilmekte ve minimum ba\u011flama a\u00e7\u0131s\u0131n\u0131n 45\u00b0\u00a0den fazla olmas\u0131 gerekmektedir. Sabit uzuv uzunlu\u011fu 100 mm olarak se\u00e7ilmi\u015ftir.<\/p>\n<p>\u03c8 = 150\u00b0, \u03bc<sub>min<\/sub>\u00a0= 45\u00b0\u00a0ve a<sub>1<\/sub>\u00a0= 100 mm olarak al\u0131nd\u0131\u011f\u0131nda denklem (8), (9) ve (11) kullan\u0131larak:<\/p>\n<p style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {{\\text{\u03bb}}^{2}}=\\frac{{\\sin \\left( {\\text{150}{}^\\circ -90{}^\\circ } \\right)}}{{\\sin \\left( {150{}^\\circ } \\right)}}=1.73205\\text{\u00a0 \u00a0}\\Rightarrow \\text{\u00a0 \u00a0\u03bb}=1.31607 <\/span><\/p>\n<p style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {{\\text{a}}_{2}}^{2}=\\frac{{\\tan \\left( {75{}^\\circ } \\right)}}{{\\tan \\left( {75{}^\\circ -45{}^\\circ } \\right)}}=6.464101\\text{\u00a0 \u00a0}\\Rightarrow \\text{\u00a0 \u00a0}{{\\text{a}}_{2}}=2.54246 <\/span><\/p>\n<p style=\"text-align: center\"><span class=\"katex-eq\" data-katex-display=\"false\"> \\displaystyle {{\\text{a}}_{3}}^{2}=\\frac{{\\sin \\left( {150{}^\\circ } \\right)}}{{\\sin \\left( {90{}^\\circ } \\right)}}\\left( {\\frac{{\\tan \\left( {75{}^\\circ } \\right)}}{{\\tan \\left( {75{}^\\circ -45{}^\\circ } \\right)}}-1} \\right)=2.73205\\text{\u00a0 \u00a0}\\Rightarrow \\text{\u00a0 \u00a0}{{\\text{a}}_{3}}=1.65289 <\/span><\/p>\n<p style=\"text-align: center\">a<sub>4<\/sub> = \u03bba<sub>3<\/sub> = 2.17533<\/p>\n<p>olur. a<sub>1<\/sub>\u00a0= 100 mm al\u0131nd\u0131\u011f\u0131nda a<sub>2<\/sub>\u00a0= 254 mm, a<sub>3<\/sub>\u00a0= 165 mm ve a<sub>4<\/sub>\u00a0= 218 mm olacakt\u0131r. Grashof kural\u0131na g\u00f6re d\u00f6rt-\u00e7ubuk mekanizmas\u0131 \u00e7ift koldur. Sonu\u00e7 \u015fekilde g\u00f6r\u00fclmektedir.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-1132\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/img2-10.gif\" alt=\"\" width=\"517\" height=\"461\" \/><\/p>\n<p>Yukar\u0131da a\u00e7\u0131klanm\u0131\u015f olan tasar\u0131m kolayca Excel program\u0131nda yap\u0131labilir. Excel k\u00fct\u00fc\u011f\u00fc i\u00e7in <a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/09\/ciftkoltasarim.xls\">t\u0131klay\u0131n\u0131z.<\/a><\/p>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div>\n\n\n<p><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch7\/7-1\/\" data-type=\"page\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-16\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/back_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch7\/\" data-type=\"page\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-17\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/contents_button.gif\" alt=\"\" \/><\/a><a href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/\" data-type=\"page\" data-id=\"47\"><img loading=\"lazy\" decoding=\"async\" width=\"38\" height=\"38\" class=\"wp-image-18\" style=\"width: 38px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/home_button.gif\" alt=\"\" \/><\/a><img loading=\"lazy\" decoding=\"async\" width=\"119\" height=\"40\" class=\"wp-image-15\" style=\"width: 119px\" src=\"https:\/\/blog.metu.edu.tr\/eresmech\/files\/2021\/04\/ceres.gif\" alt=\"\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ba\u011flama A\u00e7\u0131s\u0131 En \u0130yi Olan \u00c7ift Kol Mekanizmas\u0131 Tasar\u0131m\u0131 \u00c7ift kol mekanizmas\u0131 genel olarak d\u00fczg\u00fcn bir d\u00f6nme hareketini d\u00fczg\u00fcn olmayan bir d\u00f6nme hareketine d\u00f6n\u00fc\u015ft\u00fcrmek i\u00e7in kullan\u0131l\u0131r. De\u011fi\u015fik hareket \u00f6zellikleri i\u00e7in bazen bir kol-sarka\u00e7 mekanizmas\u0131 ile birlikte kullan\u0131labilir (\u00f6rne\u011fin zaman oran\u0131n\u0131 &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/blog.metu.edu.tr\/eresmech\/mekanizma-teknigi\/ch7\/7-1\/eniyibagacisi\/\"> <span class=\"screen-reader-text\">enIyiBagAcisi<\/span> Devam\u0131n\u0131 Oku &raquo;<\/a><\/p>\n","protected":false},"author":7747,"featured_media":0,"parent":863,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":"","_links_to":"","_links_to_target":""},"class_list":["post-1039","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/1039","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/users\/7747"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/comments?post=1039"}],"version-history":[{"count":0,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/1039\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/pages\/863"}],"wp:attachment":[{"href":"https:\/\/blog.metu.edu.tr\/eresmech\/wp-json\/wp\/v2\/media?parent=1039"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}